h^2+4h-242=0

Solution for h^2+4h-242=0 equation:

h^2+4h-242=0

a = 1; b = 4; c = -242;
Δ = b2-4ac
Δ = 42-4·1·(-242)
Δ = 984
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{984}=\sqrt{4*246}=\sqrt{4}*\sqrt{246}=2\sqrt{246}$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-2\sqrt{246}}{2*1}=\frac{-4-2\sqrt{246}}{2}
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+2\sqrt{246}}{2*1}=\frac{-4+2\sqrt{246}}{2}
$